Revert ParseCommandOverride change since it appears to be badly screwing up scripting. Need to find out why. This backs out 7f57d0c7816a and the recent workaround.
module PascalParser where
import Text.ParserCombinators.Parsec
import Control.Monad
data PascalUnit =
Program Identificator Implementation FunctionBody
| Unit Identificator Interface Implementation (Maybe Initialize) (Maybe Finalize)
deriving Show
data Interface = Interface Uses TypesAndVars
deriving Show
data Implementation = Implementation Uses TypesAndVars Functions
deriving Show
data Functions = Functions [Function]
deriving Show
data Function = Function String
deriving Show
data Identificator = Identificator String
deriving Show
data FunctionBody = FunctionBody String
deriving Show
data TypesAndVars = TypesAndVars String
deriving Show
data Initialize = Initialize Functions
deriving Show
data Finalize = Finalize Functions
deriving Show
data Uses = Uses [Identificator]
deriving Show
parsePascalUnit :: String -> Either ParseError PascalUnit
parsePascalUnit = parse pascalUnit "unit"
where
comments = skipMany (comment >> spaces)
identificator = do
spaces
l <- letter <|> oneOf "_"
ls <- many (alphaNum <|> oneOf "_")
spaces
return $ Identificator (l:ls)
pascalUnit = do
spaces
comments
u <- choice [program, unit]
comments
spaces
return u
comment = choice [
char '{' >> manyTill anyChar (try $ char '}')
, string "(*" >> manyTill anyChar (try $ string "*)")
, string "//" >> manyTill anyChar (try newline)
]
unit = do
name <- unitName
spaces
comments
int <- string "interface" >> interface
manyTill anyChar (try $ string "implementation")
spaces
comments
impl <- implementation
return $ Unit name int impl Nothing Nothing
where
unitName = between (string "unit") (char ';') identificator
interface = do
spaces
comments
u <- uses
return $ Interface u (TypesAndVars "")
program = do
name <- programName
spaces
comments
impl <- implementation
return $ Program name impl (FunctionBody "")
where
programName = between (string "program") (char ';') identificator
implementation = do
u <- uses
manyTill anyChar (try $ string "end.")
return $ Implementation u (TypesAndVars "") (Functions [])
uses = liftM Uses (option [] u)
where
u = do
string "uses"
spaces
u <- (identificator >>= \i -> spaces >> return i) `sepBy1` (char ',' >> spaces)
char ';'
spaces
return u